On Sun, Aug 3, 2008 at 8:19 PM, Manish Katiyar <[EMAIL PROTECTED]> wrote:
> On Sun, Aug 3, 2008 at 7:36 PM, Rene Herman <[EMAIL PROTECTED]> > wrote: > > >> > >> > >> How does this work ? :-( ....... Isn't gcc supposed to catch this and > >> flag warning unless I am missing something very obvious. > > > > In C, except as an operand of sizeof or unary &, an expression having > > function type is automatically converted from function type to pointer to > > function. > > > > > Or put differently: except for sizeof and unary &, "function_designator" > and > > "&function_designator" are interchangeable as expressions. > Thanks Rene. Plz discard my earlier msg as I didn't get question then. Yes it's the case with the fuctions. Just a small detail. They aren't interchangeable. "&function_designator" cannot be used in place of "function_designator". Correct me if I am wrong. - Rahul. -- Smart data structures and dumb code works a lot better than the other way around. -Eric S Raymond
