> > that also suggests that a passage on p. 91 of LKD3 is > inaccurate, where it claims that "because the lists are > circular, you can generally pass any element for head." but > that can't be right, since you must *always* keep track of > the head node for any list, to avoid processing it normally. > if you simply drop someone into the middle of a circular, > doubly-linked kernel list, there is no way that i can see to > know which node in that list is the head node when you run > across it during iteration. > > does this make sense? >
I think you are assuming that all lists have a separate list_head structure to locate the head of the list. I am not sure that is correct. For example, the task structures are linked toghether in a curcular list with no separate list_head structure. The init_task->tasks.next field is usually the starting point, but current->tasks.next should work just as well. Bruce -- To unsubscribe from this list: send an email with "unsubscribe kernelnewbies" to [email protected] Please read the FAQ at http://kernelnewbies.org/FAQ
