Hi Magnus,
Give the following a try:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0"
xmlns:marc="http://www.loc.gov/MARC21/slim"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="text" encoding="UTF-8" indent="no"/>
<xsl:template match="marc:record">
<xsl:if test="marc:datafield[starts-with(@tag,'65')]">
<xsl:for-each select="marc:datafield[starts-with(@tag,'65')]">
<xsl:if test="@tag=650">
<xsl:for-each select="marc:subfield">
<xsl:choose>
<xsl:when test="@code='2'">
<xsl:variable name="twoval" select="."/>
<xsl:if test="($twoval='x') or ($twoval='y')">
<xsl:value-of select="preceding-sibling::*[@code='a']"/>
<xsl:text>
</xsl:text>
</xsl:if>
</xsl:when>
</xsl:choose>
</xsl:for-each>
</xsl:if>
<xsl:if test="@tag!=650">
<xsl:for-each select="marc:subfield">
<xsl:choose>
<xsl:when test="@code='a'">
<xsl:value-of select="."/>
<xsl:text>
</xsl:text>
</xsl:when>
</xsl:choose>
</xsl:for-each>
</xsl:if>
</xsl:for-each>
</xsl:if>
</xsl:template>
</xsl:stylesheet>
Regards,
Andreas
P.S.: There's probably a much better way of doing this... ;-)
On 2021-03-02 14:22, Magnus Enger wrote:
Kia ora!
I want to display most keywords as usual, but with an exception for
those from the 650 field. Specifically, I want to display only those
keywords that has the value "x" or "y" in subfield $2, and hide the
other 650-keywords. Any hints on how to this in XSLT would be infinitely
appreciated, and added to the wiki, so others can benefit from the
solution.
Here is an example:
<datafield tag="650" ind1=" " ind2="0">
<subfield code="a">A</subfield>
<subfield code="2">x</subfield>
</datafield>
<datafield tag="650" ind1=" " ind2="0">
<subfield code="a">B</subfield>
<subfield code="2">y</subfield>
</datafield>
<datafield tag="650" ind1=" " ind2="0">
<subfield code="a">C</subfield>
<subfield code="2">z</subfield>
</datafield>
<datafield tag="653" ind1=" " ind2="0">
<subfield code="a">D</subfield>
</datafield>
I want to display A and B (because they have $2 = x or y), and D
(because it is not 650), but not C (because it is 650 and $2 is neither
x nor y).
Best regards,
Magnus
Libriotech
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