On 10/1/07, Anthony Liguori <[EMAIL PROTECTED]> wrote:
> Cameron Macdonell wrote:
> > Hi,
> >
> > I'm trying to understand guest virtualization at the lower levels.  I
> > have a somewhat basic question:  How does KVM virtualize an int80
> > instruction from a guest?  A pointer to an answer is just as good as
> > an answer itself.
> >
>
> The same thing happens as it does on normal hardware.
>
> The way VT/SVM works (at a high level), is that certain instructions and
> events check a special area called the VMCS/VMCB to determine whether
> the event should generate a vmexit which is really just a special type
> of trap.
>
> There are no hooks for interrupts 32-255 so the hardware operates as it
> normally would.  If you're interested in getting a trap for int80 within
> KVM, you'll have to trap sidt/lidt and virtualize the IDT.  You'll need
> to setup a fake IDT and have the int80 handler do a hypercall.  This is
> complicated if the guest is using a fast-syscall mechanism.  It may be a
> little challenging finding a piece of guest memory to take over that has
> a valid virtual mapping.

This is a bit vague to me. Why do you need "a piece of guest memory" here?

Thanks,
Jun

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