Alexander,

On Tue, Jul 26, 2011 at 19:05 +0200, Alexander Graf wrote:
> > @@ -2623,6 +2626,7 @@ static void kvm_vcpu_ioctl_x86_get_debugregs(struct 
> > kvm_vcpu *vcpu,
> >     dbgregs->dr6 = vcpu->arch.dr6;
> >     dbgregs->dr7 = vcpu->arch.dr7;
> >     dbgregs->flags = 0;
> > +   memset(&dbgregs->reserved, 0, sizeof(dbgregs->reserved));
> > }
> > 
> > static int kvm_vcpu_ioctl_x86_set_debugregs(struct kvm_vcpu *vcpu,
> > @@ -3106,6 +3110,7 @@ static int kvm_vm_ioctl_get_pit2(struct kvm *kvm, 
> > struct kvm_pit_state2 *ps)
> >             sizeof(ps->channels));
> >     ps->flags = kvm->arch.vpit->pit_state.flags;
> >     mutex_unlock(&kvm->arch.vpit->pit_state.lock);
> > +   memset(&ps->reserved, 0, sizeof(ps->reserved));
> 
> struct kvm_pit_state2 {
>         struct kvm_pit_channel_state channels[3];
>         __u32 flags;
>         __u32 reserved[9];
> };
> 
> So memset(&ps->reserved) would give you the a __u32 **, no? Same goes for all 
> the other array sets in here. Or am I understanding some C logic wrong? :)

No, the array name and an address of the array give the same address.  I
could use ps->reserved instead of &ps->reserved, but it is a question of
coding style.  I got opposite opinions on this question from different
maintainers.

Another thing is that sizeof() of the array name and the pointer to the
first array element differ.  But I used sizeof(array) here, so it should
be correct.


Thanks,

-- 
Vasiliy Kulikov
http://www.openwall.com - bringing security into open computing environments
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