Try this:
<handler name="onconstruct">
Debug.monitor(this, 'x');
Debug.monitor(this, 'y');
</handler>
On 2006-06-19, at 17:12 EDT, John Sundman wrote:
> Well, I am now officially confused about the behavior of simplelayout
> (and not for the first time).
>
> This is what I have written in the reference page now:
>
> <p><classname>simplelayout</classname> extends
> <classname>LzLayout</classname>, and therefore it is responsible for
> arranging all of the subviews for the view that it is attached to.
> <classname>simplelayout</classname>
> affects either the <attribute>x</attribute> or <attribute>y</
> attribute>
> value, depending on the value of the <attribute>axis</attribute>
> attribute. <classname>simplelayout</classname> places the first
> subview
> at (0, 0) and then places each subsequent subview based on the width
> (or height) of the previous subview, depending on which axis was
> specified.</p>
>
> However, consider the following:
>
> <canvas debug="true">
> <view >
> <simplelayout axis="y" spacing="10"/>
> <view bgcolor="blue" y="40" height="30" width="50">
> <handler name="oninit">
> Debug.write("x is " + x, "y is " + y)
> </handler>
> </view>
> <view bgcolor="blue" height="30" width="50"/>
> <view bgcolor="blue" height="30" width="50"/>
> </view>
> </canvas>
>
> No matter what values you assign to x and y of the first view, it
> always appears in the upper left corner. That is, to the eye it
> appears that it's at x=0, y=0.
>
> However, the debug statements reflect the values given to x and y in
> the opening tag.
>
> So the question comes down to, who am I going to believe, the debug
> statement or my lying eyes?
>
> Or, more likely, am I overlooking something really obvious?
>
> Thanks
>
> jrs
>
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