At 8:07 -0700 6/4/04, PJ M wrote: >If I understand properly you know %co2 and you want to >know x right ? >Therefore you just have to solve the equation. It's a >pure math problem, no a LV one. >Let's rename your equation >%CO2=(((3.10933*(X*X))+(.5602*X)))/(0.30204-X) like so >y=(ax*x+bx)/(c-x) ><=> y(c-x)=(ax*x+bx) <=> ax*x+(b+y)x-yc=0 >Then assuming than D=(b+y)*(b+y)+4yac is positif you >have the following: >x=[-b+(or-)Sqr(D)]/2a
Note! Sqr(D) is really Sqrt(D) the square ROOT of D not the square. But this right, you DO want to use the exact quadratic solution. Also I think D= (b+y)^2-4yac <http://www.sosmath.com/algebra/factor/fac08/fac08.html> Also for for future reference, equations greater than 4th order that do not have exact solutions like this, you can use the "root finding" routines built into LV. -Scott