Perhaps not the most efficient solution but that would do: // p is the integer, f.e. 208 IntToStr(p div 100) + '.' + IntToStr((p mod 100) div 10) + IntToStr(p mod 10)
On Wed, Dec 12, 2012 at 12:23 PM, Richard Mace <richard.m...@gmail.com>wrote: > Hi All, > Got a simple question that has stumped me, which tends to happen if I > don't do development for a couple of months. > > How's the best way of converting an integer number "208" (that is pence) > into a string value that is in pounds (2.08) > > Thanks as always in advance. > > Richard > > -- > _______________________________________________ > Lazarus mailing list > Lazarus@lists.lazarus.freepascal.org > http://lists.lazarus.freepascal.org/mailman/listinfo/lazarus > >
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