On 02/26/2013 09:07 AM, Sven Barth wrote:
Helpers have the same problem. For now there is only one solution (as
I already wrote): require that the type with which you specialize is a
record. Then a class operator in that record can be defined.
For the future I already have the following longterm plans:
- add class operator support to class and object
- allow to specify additional units after "specialize" that will be
used when specializing (they will be added first, so that the original
code is not unnecessarily modified)
Here a "funny" question come up:
Why do we (still) have records at all ?
We do have classes that allow for static and/or virtual methods (of
course no methods at all are possible, too. )
So why are record that now can have more than none methods. The only
difference I see is that records can reside in other places than on the
heap. But (if necessary) a certain type of class seems more straight
forward to me (of course with "record" as a synonym for compatibility) .
AFAIK even old style Turbo-Pascal "Objects" are still in place.... That
could be a certain type of class as well.
-Michael
--
_______________________________________________
Lazarus mailing list
Lazarus@lists.lazarus.freepascal.org
http://lists.lazarus.freepascal.org/mailman/listinfo/lazarus
