> The length of a Martian solar day is currently about 88775.24409 s (per > Wikipedia), yielding an average minute length for a UTC equivalent of > 61.6494751 s. On Paleoterra you'll want an average minute length somewhere > between 58.0 s and 59.4 s. So on Mars you'll want about 65% of minutes to be > 62 seconds long and the rest 61 seconds long. There'll have to be alternation > of minutes within each day, which could be mostly according to a regular > pattern,
That's one way to do it, certainly. Another way is to have TAI hours and minutes and seconds, with each day ending with a partial hour. Digital time displays would have no problem with this, calculators can be used if you actually need to work out how long an interval stretching over midnight was, and analogue clocks and watches become intriguing gadgets (noting it's no more difficult than my radio-controlled clock that moves its hands around to correct the time, or my wristwatch whose analogue stopwatch winds back when I reset it or forwards when I end a pause). -- Clive D.W. Feather | If you lie to the compiler, Email: cl...@davros.org | it will get its revenge. Web: http://www.davros.org | - Henry Spencer Mobile: +44 7973 377646 _______________________________________________ LEAPSECS mailing list LEAPSECS@leapsecond.com http://six.pairlist.net/mailman/listinfo/leapsecs
