On Dec 1, 2009, at 8:17 AM, Johann Klähn wrote: > Ok, but then 0,18€ has to be the price for 1l. How do I enter the > price for 1.5l? (Which would be more convenient and works with my > clumsy method).
(1l {=0,18€} * 1.5 * 6)?
John
On Dec 1, 2009, at 8:17 AM, Johann Klähn wrote: > Ok, but then 0,18€ has to be the price for 1l. How do I enter the > price for 1.5l? (Which would be more convenient and works with my > clumsy method).
(1l {=0,18€} * 1.5 * 6)?
John