On Sep 4, 3:09 pm, Terry Brown <[email protected]> wrote:
> w/o xpath, it's somehow search for the element with @id='co_text_holder', and
> then somehow find its parent.
How about this? ::
import xml.etree.ElementTree as etree
path = r'C:\leo.repo\inkcall\template.svg'
root = etree.parse(path).getroot()
print('='*30)
d = {}
def computeParents(d,e):
for child in e.getchildren():
d[child] = e
computeParents(d,child)
computeParents(d,root)
for key in d.keys():
print('child: %9s parent: %9s' % (id(key),id(d.get(key))))
Edward
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