Without any measurement I think that this can be further simplified and
speed up. The all_positions_for_v builds and yields positions, which means
it builds entire stacks of (v, index) pairs for each visited v node. And
for marking dirty parents it doesn't need to build positions at all. The
following is not tested but I believe it should work.
def collect_dirty_parents(v):
def it(ch):
yield ch
for par in ch.parents:
yield from it(par)
dirty_nodes = [x for x in it(v) if x.isAnyAtFileNode() and not x.isDirty
()]
for x in dirty_nodes:
x.setDirty()
return dirty_nodes
Vitalije
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