Hi, On a machine with 1GB RAM, I booted an lguest guest with 256MB memory as follows: ./lguest --block='blockfile' --initrd=/boot/initrd.img-2.6.23-rc9 256m /boot/vmlinuz-2.6.23-rc9 root=/dev/lgba rw single
The size of /proc/kcore file in the host obtained using 'ls -la' is 1073422336, while the same command executed within the guest shows the size as 1069228032. Since the size of /proc/kcore represents the size of the physical memory (RAM), and I boot the guest with just 256MB of memory, shouldn't the size of the kcore file under guest be 256MB instead of around 1GB? Will the contents of /proc/kcore in the guest also reflect the contents of the host memory? Please let me know. Thanks! Sujit
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