I believe you need to first check DofObject::n_comp() for the node to make sure 
it's not 0. 



On Feb 15, 2013, at 11:02 AM, "Subramanya Gautam Sadasiva" 
<[email protected]> wrote:

> Hi , 
> I knew that that was the way things were implemented. The main problem seems 
> to be that I am using the snes-vi solver and to apply the bounds , I do 
> 
> 
> 
>  MeshBase::const_node_iterator node_it = _solbub._mesh->local_nodes_begin(); 
>  const MeshBase::const_node_iterator node_it_end = 
> _solbub._mesh->local_nodes_end(); 
>  for (;node_it!=node_it_end;node_it++)
> 
>    {
> 
>      Node* node = *node_it;
> 
>       const unsigned int dofnum_phi = node->dof_number(sys_num,phi_var,0);
>       const unsigned int dofnum_mu = node->dof_number(sys_num,mu_var,0);
> 
> 
>    }
> 
> This causes a segmentation fault. I guess the node iterator goes over ALL the 
> nodes that it sees. How do I check if dof_number is returning something 
> meaningful? Sorry my first email was a bit hasty. I sent it before I 
> localized the error. 
> 
> Thanks, 
> 
> Subramanya Sadasiva 
> 
> "But memory eventually fades. Turbulences damp out, internal strains yield to 
> plastic flow, concentration inhomogeneities diffuse to uniformity. Systems 
> tend to subside to very simple states,independent of their specific history."
> Herbert Callen . Thermodynamics and an Introduction to Thermostatics.
> 
> ----- Original Message -----
> From: "David Knezevic" <[email protected]>
> Cc: [email protected]
> Sent: Friday, February 15, 2013 11:54:28 AM
> Subject: Re: [Libmesh-users] Multiple equatiosn with different orders of    
> interpolation
> 
> 
> On 02/15/2013 11:48 AM, Kirk, Benjamin (JSC-EG311) wrote:
>> 
>> On Feb 15, 2013, at 10:41 AM, "David Knezevic" <[email protected]> 
>> wrote:
>> 
>>> On 02/15/2013 11:39 AM, Subramanya Gautam Sadasiva wrote:
>>>> Hi,
>>>> I am trying to solve a problem with multiple system objects as part of the 
>>>> same equation syztems object. One of them ( A navier stokes solver ) needs 
>>>> quad9 elements and the other one a cahn hilliard solver, I want to solve 
>>>> using QUAD4 elements. Is this possible on a single mesh?. The code does 
>>>> not work when I try to do this.
>>> Sure, that should be no problem.
>>> 
>>> David
>> The trick is the difference between geometric elements and finite elements. 
>> Your mesh will need Quad9 geometric elements, but you can add bilinear, 
>> biquadratic, hierarchic, whatever finite element approximations.
> 
> Yes, sorry my post didn't actually point out the answer!
> 
> 
> 
> 
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