https://bugs.documentfoundation.org/show_bug.cgi?id=150185
Rafael Lima <rafael.palma.l...@gmail.com> changed:
What |Removed |Added
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CC| |rafael.palma.l...@gmail.com
--- Comment #3 from Rafael Lima <rafael.palma.l...@gmail.com> ---
As pointed out by Mike, using Object or Variant as the type of p(0) will work.
Sub Test1
Dim p(0) As Object
Dim h As New com.sun.star.awt.Point
h.X=1
p(0)=h
Msgbox "h.X=" & h.X & " p(0).X=" & p(0).X
End Sub
Now one thing bent my mind. Although printing p(0).X returns 0, if you inspect
p(0) using XRay Tool you'll see that X = 1 inside p(0). What gives?
Sub Test2
Dim p(0) As New com.sun.star.awt.Point
Dim h As New com.sun.star.awt.Point
h.x = 1
p(0) = h
MsgBox p(0).X ' Prints 0
XRay p(0) ' Here p(0).X is equal to 1
End Sub
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