Re-ordering paragraphs... > Not on all systems, but I think that will happen with gcc/ld though. > I think they will only export dllexported symbols if at least one such > symbol exist. However, this causes some trouble if you e.g. have a > library that is not decorated with dllexport and which uses ltdl as a > convinience library. Since ltdl is decorated with dllexport, only the > ltdl symbols are exported in that case, which of course is not what > you generally want...
Using ltdl seems like the more complicated case. Clearly I'm biased, but requiring extra work to prepare a library for ltdl seems more natural than the other way around. > This is by design. For the msvc branch, libtool digs > through the object files to get all public symbols and > exports those, regardless of any dllexport decorations. This is a bit surprising. If gcc/ld doesn't do it, and msvc doesn't do it, why does libtool do it by default? > > What can I do to convince libtool to keep function foo > > hidden? > > Use one of the -export-symbols SYMFILE or > -export-symbols-regex REGEX options. Whether it's the default or not, is there some way to convince libtool to look at the __declspec(export) decorations I've already got in place? -DB _______________________________________________ http://lists.gnu.org/mailman/listinfo/libtool
