Am 03.07.2012 09:26, schrieb Ludovic Rousseau:
> 2012/7/3 Tobias Powalowski <tobias.powalow...@googlemail.com>:
>> Am 03.07.2012 08:49, schrieb Ludovic Rousseau:
>>> Why is the lib called libusb.a and not libusb-1.0.a?
>>>
>>> My hypothesis is that libusb.a comes from libusb-compat and is not
>>> (statically) linked with libusb (or libusbx). So of course all the
>>> libusb-1.0 symbols are missing.
>>> Can you check that?
>> Correct, does that mean i need to rebuild libusb-compat against libusbx?
> Your dynamic libusb-compat lib (libusb.so) should be linked with
> libusb-1.0. Check with ldd(1).
> Is that the case?
linux-vdso.so.1 => (0x00007fff38ad2000)
libusb-1.0.so.0 => /usr/lib/libusb-1.0.so.0 (0x00007f3a82161000)
libc.so.6 => /lib/libc.so.6 (0x00007f3a81dc0000)
librt.so.1 => /lib/librt.so.1 (0x00007f3a81bb7000)
libpthread.so.0 => /lib/libpthread.so.0 (0x00007f3a8199b000)
/lib/ld-linux-x86-64.so.2 (0x00007f3a825a2000)
> And the libusb.so lib should not have any missing symbol. Check with "ldd -r"
> Is that also the case?
ldd -r /usr/lib/libusb.so
linux-vdso.so.1 => (0x00007fff3a1ff000)
libusb-1.0.so.0 => /usr/lib/libusb-1.0.so.0 (0x00007f549794e000)
libc.so.6 => /lib/libc.so.6 (0x00007f54975ad000)
librt.so.1 => /lib/librt.so.1 (0x00007f54973a4000)
libpthread.so.0 => /lib/libpthread.so.0 (0x00007f5497188000)
/lib/ld-linux-x86-64.so.2 (0x00007f5497d8f000)
>>> Another good idea is to NOT distribute a static lib. Only the dynamic
>>> .so should be provided. But that is not the problem.
>> I already disabled static lib in libusbx.
> So you can't build a libusb-compat static lib without a libusb(x) 1.0
> static version.
> Disable static lib for libusb-compat as well.
>
Thanks will also disable it.
Looks like all is ok and i only need to remove the static libusb-compat
file.
greetings
tpowa
--
Tobias Powalowski
Archlinux Developer & Package Maintainer (tpowa)
http://www.archlinux.org
tp...@archlinux.org
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