Is there anything to stop you defining an class/entity {answer: String,
countAnswer: Int} and to directly create it from JPA (of course, it's read
only).

On Wed, Apr 22, 2009 at 9:36 AM, Charles F. Munat <c...@munat.com> wrote:

>
> I was thinking tuples, but that didn't work. I'll try your suggestion.
> BTW, for anyone reading along, I forgot the group by clause in the query
> below.
>
> Chas.
>
> Derek Chen-Becker wrote:
> > I think that the type would be Array[Any] and you'll get one String and
> > Int for each row.
> >
> > Derek
> >
> > On Tue, Apr 21, 2009 at 3:37 PM, Charles F. Munat <c...@munat.com
> > <mailto:c...@munat.com>> wrote:
> >
> >
> >     Anyone have a quick example of how to run a scalar query in JPA? I
> can't
> >     find anything in the JPA demo.
> >
> >     I have this query:
> >
> >     select t.answer, count(distinct answer) from Vote t where t.poll =
> :poll
> >     order by t.answer
> >
> >     but how do I call it? I normally do:
> >
> >     Model.createNamedQuery[...]("findVoteCountAnswersByPoll", "poll" ->
> >     poll).findAll
> >
> >     But what is the type? And how do I get the results back out?
> >
> >     I know I did this once before somewhere, but I can't remember where
> and
> >     I can't find it.
> >
> >     Thanks!
> >
> >     Chas.
> >
> >
> >
> >
> > >
>
> >
>

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