Henrik Frisk <[EMAIL PROTECTED]> writes: > Rather than using a keyword, if the function is called with divtwo==0 > use equal divisor. In other words: (compound-time grob 3 8 5 8) would > result in 3/8+5/8 and (compound-time grob 3 8 5 0) would give 3+5/8 > (as I believe it's a matter of taste what way you want to notate > it). Does that make sense? Maybe a keyword makes it simpler to > understand?
I said to use the keyword or "detect the behavior automatically" which I really prefer. if the list of arguments is equal to 4 the expected arguments would be (numerator1 denominator1 numerator2 denominator2) like: (compound-time grob 3 16 5 8) if the list of arguments is 3 the arguments would be (numerator1 numerator2 denominator), like (compound-time grob 3 5 8) the implementation of it would use optional arguments as described by Han-Wen. Pedro _______________________________________________ lilypond-user mailing list lilypond-user@gnu.org http://lists.gnu.org/mailman/listinfo/lilypond-user
