It is because a score block, ie. \score { ... } can only contain the
following:
- one music expression OR one score identifier (a score defined as a
variable)
- THEN zero or more header, output definition or object_id_setting
\set Score.skipBars = ##t in itself is a music expression, so in your
first snippet the score would contain 2 music expression (the \new Staff
and the \set). It is not allowed.
However you could have used
\score { <<
\new Staff = bla <<
\new voice =blu {\voiceOne \Sopran}
\new voice =blu {\voiceTwo \Alt} >>
\set Score.skipBars = ##t
}
because << will mean simultaneous music and will make its content 1 expression
Werner írta:
Hello,
I've written a file containing a score with a structure like:
\score {
\new Staff = bla <<
\new voice =blu {\voiceOne \Sopran}
\new voice =blu {\voiceTwo \Alt} >>
}
Wanted to put the
\set Score.skipBars = ##t
command in.
This:
\score {
\new Staff = bla <<
\new voice =blu {\voiceOne \Sopran}
\new voice =blu {\voiceTwo \Alt} >>
\set Score.skipBars = ##t
}
brings syntax error unexpected \set
This
\score {
\new Staff = bla <<
\new voice =blu {\voiceOne \Sopran}
\new voice =blu {\voiceTwo \Alt}
\set Score.skipBars = ##t >>
}
works.
For me this is very strange.
Also the documentation gives no hint about...
Could somebody explain that?
WM
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