Il giorno mar, 03/05/2011 alle 17.22 +0200, Peter Crighton ha scritto:
> Is it possible to connect arpeggios between two different voices in a
> TabStaff?
> I can get the desired output by overriding Arpeggio #'positions, but
> I'd like to have a more intuitive way, something like
> \set TabStaff.connectArpeggios = ##t
> Is there a better way, am I just missing something?
>
>
> Also I'd like to know why I have to put an \RemoveEmptyStaffContext in
> the layout in order to get Span_arpeggio_engraver to work.
> For most of my scores I need \RemoveEmptyStaffContext, which is why it
> was there in the first place. I don't need it for the current one
> though, so I'd like to leave it out, but then the whole Arpeggio
> connecting doesn't work anymore.
>
>
> See the attachment for my (reduced) code. (By the way, the problem
> exists in 2.13.61 as well.)
> _______________________________________________
Have you tried some of the snippets in the LSR?
http://lsr.dsi.unimi.it/LSR/Search?q=arpeggio
If you apply connectArpeggios to the Score context you can comment
\RemoveEmptyStaffContext, but I guess that the result is not what you
are expecting.
BTW, why entering the music twice, once for Staff and once for TabStaff?
See attached example.
Cheers,
Federico
\version "2.12.3"
first = \relative c' {
\set Score.connectArpeggios = ##t
<a d e>4\arpeggio d a d
}
second = \relative c {
d1\arpeggio
}
\score {
\new StaffGroup <<
\new Staff = "guitar" <<
\context Voice = "first voice" { \clef "G_8" \voiceOne \first }
\context Voice = "second voice" { \clef "G_8" \voiceTwo \second }
>>
\new TabStaff = "tab" <<
\context TabVoice = "tab first voice" { \voiceOne \first }
\context TabVoice = "tab second voice" { \voiceTwo \second }
>>
>>
\layout {
\context {
\Score
%\RemoveEmptyStaffContext
\consists "Span_arpeggio_engraver"
}
}
}
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