Sorry,
it must have to do with my mail-program (googlemail).
I will take care in the future.
Here is the beginning of the theme.
> Dear community,
> I have a problem with subdivided beams in a 5/16 bar.
> I want to have subbeams of irregular length, grouped in 2+3 16ths.
> Unfortunately it doesn't work.
> Is there a way to realize it?
> Here is a short snippet:
>
> \version "2.14.2"
> motif = \relative c' { c16[ d e f g] }
> \new Staff {
> \time 5/16
> \motif
> \set subdivideBeams = ##t
> \context Voice << {\motif}
> { \set baseMoment = #(ly:make-moment 1 8) s8
> \set baseMoment = #(ly:make-moment 3 16) s8. % only two notes are
> beamed together, not three!
> }>>
> }
>
2011/12/31 Hans Aberg <haber...@telia.com>
> You did not have the cc on this mail either, so others do not know that
> you consider the issue solved.
>
> Hans
>
>
> On 31 Dec 2011, at 10:24, Stefan Thomas wrote:
>
> > Dear Hans,
> > thanks, it works fine now!
> > Sorry for not having included the copy in my answer, I thought I did.
> > Best wishes to the new Year to all lilypond users, especially to all,
> who helped to develop this great piece of software!
> >
> > 2011/12/30 Hans Aberg <haber...@telia.com>
> > [Please keep the cc to the list, so that others can follow the issue.]
> >
> > On 30 Dec 2011, at 21:34, Stefan Thomas wrote:
> >
> > > Dear Hans,
> > > thanks for Your reply, but it was a misunderstanding.
> > > I know how to beam in 2+3 in 5/16 bar, but I would like to know if I
> can make subbeams, grouped in 2+3.
> > > With Your code it doesn't work for me, at least with version 2.14.2
> >
> > No, I think that is a current shortcoming on the meter level. One can
> specify each subbeaming as follows:
> >
> > motif = \relative c' { c16[
> > \set stemLeftBeamCount = #2
> > \set stemRightBeamCount = #1
> > d
> > \set stemLeftBeamCount = #1
> > \set stemRightBeamCount = #2
> > e
> > \set stemLeftBeamCount = #2
> > f g]
> > }
> >
> > One can also use
> > \set baseMoment = #(ly:make-moment 2 16)
> > but it breaks the subbeams at every multiple of 2/16.
> >
> > Hans
> >
> >
> >
> >
>
>
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