Pierre Perol-Schneider <pierre.schneider.pa...@gmail.com> writes:
> Hi,
>
> I'd like to understand why the following function has no effect :
>
> %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
>
> \version "2.19.3"
>
>
> myFunctionFalse = \override Score.BarNumber.break-visibility = ##(#f #f #f)
>
> myFunctionTrue = \override Score.BarNumber.break-visibility = ##(#f #t #t)
>
>
> myFunction =
>
> #(define-music-function (parser location arg) (boolean?)
>
> #{
>
> \override Score.BarNumber.break-visibility = ##(#f $arg $arg)
>
> #})
The symbol $arg is likely a mistake, but the symbol arg would not be
better. Please note that #(...) is the syntax for a _constant_ vector.
All its contents are quoted. With #f, this does not make a difference.
But arg remains arg.
So you probably want to write ... = #(vector #f arg arg) instead. That
way arg is not quoted.
--
David Kastrup
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