Rob/Shane,
I appreciate your overnight assistance, I did modify the script to look
at all pids, with the same result.
I do realize that linux memory mgmt is lazy (delayed cache writes) and
that is why I was wondering if I can't find which current pid
has swap allocations, is there a way to run the swap chain to see what
process held it in the past.
From the looks of this system, I suspect an overnight backup process
utilizing the full memory allocation and populating swap. That process
then finishes but swap doesn't' clear because of it's "lazy" attributes.
Phil
On Thu, Apr 12, 2012 at 6:37 AM, Rob van der Heij wrote:
On Thu, Apr 12, 2012 at 11:02 AM, Shane G <ibm-m...@tpg.com.au> wrote:
No, by lazy in this context I meant that freed memory (pages) are not
immediately moved to the free list. This even extends to task
termination.
If memory pressure ramps up sufficiently, kswapd will get kicked to
balance
out the trees. Could take a while - like forever.
In addition to what Rob mentioned, there is de-dup and compressed
swap cache
out in the wild already. How does the mug end user figure out what's
what ?.
Hmm... when I add things up from smaps, my number is higher than what
"free" says. I see VMA's like
3fffd5d3000-3fffd5d7000 r--p 0017c000 5e:01 98592
/lib64/libc-2.11.3.so
Size: 16 kB
Rss: 8 kB
Pss: 6 kB
Shared_Clean: 4 kB
Shared_Dirty: 0 kB
Private_Clean: 4 kB
Private_Dirty: 0 kB
Referenced: 0 kB
Anonymous: 8 kB
AnonHugePages: 0 kB
Swap: 8 kB
KernelPageSize: 4 kB
MMUPageSize: 4 kB
Locked: 0 kB
With 22 processes having this mapped, I would count it as 22 times 8
kB while it really is just 8 kB on swap? And how come part of this is
private when it's read-only?
Rob
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