On Wed, Jul 21, 2010 at 08:56:20PM +0200, JohnLM wrote:

> I think this should reduce problems with two conversions to/from
> floats, when both inputs and outputs are of integer type.

It doesn't and there are no such problems. Once you have a float,
multiplying or dividing it by 2^N just means changing the exponent.
It's exact. Your 'original' floats are no more precise than those
that have been reduced to [-1..+1].

Ciao,

-- 
FA,

There are three of them, and Alleline.

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