One would think with a sequential cutoff of only 1024 bytes, 2 sectors, that 
every sector would bypass the write cache:

# cat /sys/block/bcache0/bcache/sequential_cutoff; cat 
/sys/block/bcache1/bcache/sequential_cutoff
1.0k
1.0k

But as we can see a massive number of sectors are being cached:

# cat /sys/block/bcache0/bcache/dirty_data; cat 
/sys/block/bcache1/bcache/dirty_data
101G
101G

Am I misunderstanding the (sparse) documentation and not tuning correctly, or 
is there another problem?  I suspect bcache's 128 entry tracking table is 
insufficient for our workload.  If this is correct, is there any way to 
increase the size of this table?

Thanks,
Stan



On 10/03/2014 09:22 PM, Stan Hoeppner wrote:
> Hello fellow bcache users/developers,
> 
> A couple of questions.
> 
> 1.  How do I disable write caching?
> 2.  How do I increase the sequential IO tracking window from 128 IOs to say 
> 4096 IOs or nmore?
> 
> Our application does small random reads and data is never read twice, so we 
> don't want any read caching.  Reads comprise less than 20% of the IO 
> workload.  It writes ~800 streams to hundreds of preallocated files in 
> parallel using O_DIRECT and AIO.  The stream rates vary from ~50MB/s to less 
> than 2KB/s.  bcache currently seems to be writing a lot of data to cache that 
> should be going directly to the two RAID LUNs, bcache0 and bcache1.  These 
> each show over 150GB cache used or 300GB total of a 400GB SSD, with only 10GB 
> bypassed.  It seems to be writing sequential IO to cache because it's unable 
> to properly classify it due to the small 128 entry tracking window.  Thus 
> throughput is actually about 20 lower than direct to LUN.  It seems clear 
> bcache isn't doing the right thing with classification due to the large 
> number of mixed sequential/random IOs in flight.
> 
> The boxes have 32 cores and 256GB of RAM so we have plenty of horsepower and 
> memory to dedicate to bcache use.  These boxes are totally IO bound with 
> little CPU/memory use.
> 
> Please advise.
> 
> Thanks,
> Stan
> 
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