Pessoal,
Estou tentando gerar uma acl no servidor LDAP, com a linha abaixo :
access to dn="ou=(.+), ou=personal_addressbook, dc=example, dc=com"
by dn="uid=$1, dc=example, dc=com" write
by * none
Vem essa mensagem de erro, acredito que pode ser erro de sintaxe, nao tem
muita experiencia com LDAP, alguem sabe como resolver isto ?
Preparing LDAP database...
/etc/openldap/slapd.conf: line 78: expecting <what> got "ou"
<access clause> ::= access to <what> [ by <who> <access> [ <control> ] ]+
<what> ::= * | [dn[.<dnstyle>]=<DN>] [filter=<filter>] [attrs=<attrspec>]
<attrspec> ::= <attrname> [val[/<matchingRule>][.<attrstyle>]=<value>] |
<attrlist>
<attrlist> ::= <attr> [ , <attrlist> ]
<attr> ::= <attrname> | @<objectClass> | !<objectClass> | entry | children
<who> ::= [ * | anonymous | users | self | dn[.<dnstyle>]=<DN> ]
[ realanonymous | realusers | realself | realdn[.<dnstyle>]=<DN> ]
[dnattr=<attrname>]
[realdnattr=<attrname>]
[group[/<objectclass>[/<attrname>]][.<style>]=<group>]
[peername[.<peernamestyle>]=<peer>] [sockname[.<style>]=<name>]
[domain[.<domainstyle>]=<domain>] [sockurl[.<style>]=<url>]
[ssf=<n>] [transport_ssf=<n>] [tls_ssf=<n>] [sasl_ssf=<n>]
<style> ::= exact | regex | base(Object)
<dnstyle> ::= base(Object) | one(level) | sub(tree) | children | exact |
regex
<attrstyle> ::= exact | regex | base(Object) | one(level) | sub(tree) |
children
<peernamestyle> ::= exact | regex | ip | path
<domainstyle> ::= exact | regex | base(Object) | sub(tree)
<access> ::= [[real]self]{<level>|<priv>}
<level> ::= none|disclose|auth|compare|search|read|{write|add|delete}|manage
<priv> ::= {=|+|-}{0|d|x|c|s|r|{w|a|z}|m}+
<control> ::= [ stop | continue | break ]
Att,
Rodrigo Faria Tavares
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