On 20 February 2014 02:49, Gui Hecheng <guihc.f...@cn.fujitsu.com> wrote:
> When exec btrfs-debug-tree as non-root user, we get a segment fault.
> Because the btrfs_scan_block_devices return a success 0 when we fail
> to open a device. Now we just return the errno if this case happens.
>
> Signed-off-by: Gui Hecheng <guihc.f...@cn.fujitsu.com>
> ---
>  utils.c | 3 ++-
>  1 file changed, 2 insertions(+), 1 deletion(-)
>
> diff --git a/utils.c b/utils.c
> index 97e23d5..1878abc 100644
> --- a/utils.c
> +++ b/utils.c
> @@ -1517,7 +1517,8 @@ scan_again:
>                 scans++;
>                 goto scan_again;
>         }
> -       return 0;
> +
> +       return errno ? -errno : 0;
>  }
>
>  u64 parse_size(char *s)
> --
> 1.8.1.4

Hi Gui,

This strikes me as not not right because errno is only documented as
being set when open() returns -1 on failure.  In the success case
errno is not set so you can't assume it will be 0.

I think the following might work:
1) Initilase ret = 0 at the start of btrfs_scan_block_devices()
2) In the open(fullpath, O_RDONLY) failure case set ret = fd
3) return ret

Thanks,
Mike
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