On Tue, May 20, 2014 at 02:36:48PM +0800, Anand Jain wrote:
> From: Anand Jain <anand.j...@oracle.com>
>
> generally if you use
> echo "test" > /sys/fs/btrfs/<fsid>/label
> it would introduce return char at the end and it can not
> be part of the label. The correct command is
> echo -n "test" > /sys/fs/btrfs/<fsid>/label
>
> This patch will check for this user error
>
> Signed-off-by: Anand Jain <anand.j...@oracle.com>
> ---
> v2: accepts review comments. Thanks Eric and Roman
>
> fs/btrfs/sysfs.c | 20 +++++++++++++++++---
> 1 files changed, 17 insertions(+), 3 deletions(-)
>
> diff --git a/fs/btrfs/sysfs.c b/fs/btrfs/sysfs.c
> index c5eb214..ca63fcd 100644
> --- a/fs/btrfs/sysfs.c
> +++ b/fs/btrfs/sysfs.c
> @@ -373,22 +373,36 @@ static ssize_t btrfs_label_store(struct kobject *kobj,
> struct btrfs_trans_handle *trans;
> struct btrfs_root *root = fs_info->fs_root;
> int ret;
> + char *label;
> + char *pos;
>
> - if (len >= BTRFS_LABEL_SIZE) {
> + label = kzalloc(len, GFP_NOFS);
You can avoid allocating the buffer entirely:
- search for '\n', if found, use only that amount of bytes
- check for maximum size, copy to label if ok
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