On Mon, May 28, 2018 at 10:43:29PM +0800, Anand Jain wrote:
> btrfs_free_extra_devids() is called only in the mount context which
> traverses through the fs_devices::devices and frees the orphan devices
> devices in the given %fs_devices if any. As the search for the orphan
> device is limited to fs_devices::devices so we don't need the global
> uuid_mutex.
> 
> There can't be any mount-point based ioctl threads in this context as
> the mount thread is not yet returned. But there can be the btrfs-control
> based scan ioctls thread which calls device_list_add().
> 
> Here in the mount thread the fs_devices::opened is incremented way before
> btrfs_free_extra_devids() is called and in the scan context the fs_devices
> which are already opened neither be freed or alloc-able at
> device_list_add().
> 
> But lets say you change the device-path and call the scan again, then scan
> would update the new device path and this operation could race against the
> btrfs_free_extra_devids() thread, which might be in the process of
> free-ing the same device. So synchronize it by using the
> device_list_mutex.
> 
> This scenario is a very corner case, and practically the scan and mount
> are anyway serialized by the usage so unless the race is instrumented its
> very difficult to achieve.
> 
> Signed-off-by: Anand Jain <anand.j...@oracle.com>
> ---
> (I didn't see this email in the mailing list, so trying again).
> v3->v4: As we traverse through the seed device, fs_device gets updated with
>       the child seed fs_devices, so make sure we use the same fs_devices
>       pointer for the mutex_unlock as used for the mutex_lock.

Well, now that I see the change, shouldn't we always hold the
device_list_mutex of the fs_devices that's being processed? Ie. each
time it's switched, the previous is unlocked and new one locked.
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