On Thu, Jun 14, 2007 at 01:47:19PM +0200, Sebastian Siewior ([EMAIL PROTECTED])
wrote:
> * Evgeniy Polyakov | 2007-06-14 14:57:45 [+0400]:
>
> >On Thu, Jun 14, 2007 at 12:20:06AM +0200, Sebastian Siewior ([EMAIL
> >PROTECTED]) wrote:
> >> static void xor_64(u8 *a, const u8 *b, unsigned int bs)
> >> {
> >> +#if BITS_PER_LONG == 64
> >> + ((u64 *)a)[0] ^= ((u64 *)b)[0];
> >> +#else
> >> ((u32 *)a)[0] ^= ((u32 *)b)[0];
> >> ((u32 *)a)[1] ^= ((u32 *)b)[1];
> >> +#endif
> >> }
> >
> >What about endianess?
>
> It doesn't effect the xor operation. Either I load both LE, xor, store
> LE or load both BE, xor, store BE. The result is always the same. An
> additional endian convert would make thinks just slower.
> Since you confused me a little, I tested it on ppc and amd64 :)
Yeah, logic is correct for both endian.
--
Evgeniy Polyakov
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