Em Thu, 30 Mar 2017 10:26:32 -0400 (EDT)
Alan Stern <st...@rowland.harvard.edu> escreveu:
> On Thu, 30 Mar 2017, Oliver Neukum wrote:
>
> > > Btw, I'm a lot more concerned about USB storage drivers. When I was
> > > discussing about this issue at the #raspberrypi-devel IRC channel,
> > > someone complained that, after switching from the RPi downstream Kernel
> > > to upstream, his USB data storage got corrupted. Well, if the USB
> > > storage drivers also assume that the buffer can be continuous,
> > > that can corrupt data.
>
> >
> > They do assume that.
>
> Wait a minute. Where does that assumption occur?
>
> And exactly what is the assumption? Mauro wrote "the buffer can be
> continuous", but that is certainly not what he meant.
What I meant to say is that drivers like the uvcdriver (and maybe network and
usb-storage drivers) may allocate a big buffer and get data there on some
random order, e. g.:
int get_from_buf_pos(char *buf, int pos, int size)
{
/* or an equivalent call to usb_submit_urb() */
usb_control_msg(..., buf + pos, size, ...);
}
some_function ()
{
...
chr *buf = kzalloc(4, GFP_KERNEL);
/*
* Access the bytes at the array on a random order, with random size,
* Like:
*/
get_from_buf_pos(buf, 2, 2); /* should read 0x56, 0x78 */
get_from_buf_pos(buf, 0, 2); /* should read 0x12, 0x34 */
/*
* the expected value for the buffer would be:
* { 0x12, 0x34, 0x56, 0x78 }
*/
E. g. they assume that the transfer URB can work with any arbitrary
pointer and size, without needing of pre-align them.
This doesn't work with HCD drivers like dwc2, as each USB_IN operation will
actually write 4 bytes to the buffer.
So, what happens, instead, is that each data transfer will get four
bytes. Due to a hack inside dwc2, with checks if the transfer_buffer
is DWORD aligned. So, the first transfer will do what's expected: it will
read 4 bytes to a temporary buffer, allocated inside the driver,
copying just two bytes to buf. So, after the first read, the
buffer content will be:
buf = { 0x00, x00, 0x56, 0x78 }
But, on the second read, it won't be using any temporary
buffer. So, instead of reading a 16-bits word (0x5678),
it will actually read 32 bits, with 16-bits with some random value,
causing a buffer overflow. E. g. buffer content will now be:
buf = { 0x12, x34, 0xde, 0xad }
In other words, the second transfer corrupted the data from the
first transfer.
Thanks,
Mauro
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