you'll have to include the definition in ur c++ prog within the extern
statements braces ...
extern "C" {
extern void funky(void);
}
this is because C++ appends info redgarding the argument types to the fn
name, so that overloading and the likes can be performed. this is called
name mangling if u want the correct terms. by using the extern "C" you
tell the compiler to cut the name mangling from your fn as it has been
compiled externally from the C++ compiler, and thus has no such info.
regarding the argument types.
On Fri, 9 Apr 1999, John wrote:
> I have been trying for a couple of weeks now to compile a program that
> consists of a C++ main function which calls a C function. I have tried
> using the -c option to compile object code for both files using gcc and
> g++, then linking them together (I've trued using both gcc and g++ to
> link the object code). However when I try the final link together I get
> an error saying that there was an undefined reference to the C function
> in the main function.
>
> Here is the test code I have been using (I know there is no reason why
> I can't compile them both as C or C++ but they are not the functions I
> need to compile, only test ones. It makes sense to me. The final code I
> create will involve RPC calls which I can only get working in C)
>
> //C++ main function called main.cc
> extern void funky(void);
>
> void main()
> {
> funky();
> };
>
> //C function called funky.c
> void funky()
> {
> int x;
> x = 0;
> };
>
>
> The commands I used were
> g++ -c main.cc
> gcc -c funky.c
> g++ main.o funky.o -o prog
>
> I am sorry to bother you with this question but I don't know who else
> to try, even my leactures at university don't know how to achieve this.
> --
> John, My reality check just bounced.
>
>
>
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