On 21/1/19 3:15 am, Thomas Osterried wrote:
=> Even if you try to use lowercase characters (what will break supposely every
existing packet-radio-software), due to the left shift, you won't be able to
encode letters p-z.
That I find interesting… it's a 7-bit ASCII character in an 8-bit field.
'p' is 0x70 (0b01110000) according to `man ascii`, which left shifted
with be 0xe0 (0b11100000).
'z' is 0x7a (0b01111010), which left shifted would be 0xf4 (0b11110100).
Why wouldn't it be possible to encode those letters?
--
Stuart Longland (aka Redhatter, VK4MSL)
I haven't lost my mind...
...it's backed up on a tape somewhere.
