Torsten Kaiser wrote:
On 11/1/07, Jeff Garzik <[EMAIL PROTECTED]> wrote:
+       lo = tf->lbam;
+       hi = tf->lbam;
+       ibyte = (hi << 8) | lo;
+
+       lo = result_tf->lbam;
+       hi = result_tf->lbam;

That doesn't look right.
I suspect this was intended:

lo = tf->lbam;
hi = tf->lbah;

Agreed, will correct.

Thanks,

        Jeff



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