Hi Daniel,
On Tue, Oct 20, 2015 at 09:28:07AM +0200, Daniel Wagner wrote:
> +
> +/*
> + * The thing about the wake_up_state() return value; I think we can ignore
> it.
> + *
> + * If for some reason it would return 0, that means the previously waiting
> + * task is already running, so it will observe condition true (or has
> already).
> + */
> +void swake_up_locked(struct swait_queue_head *q)
> +{
> + struct swait_queue *curr;
> +
> + list_for_each_entry(curr, &q->task_list, task_list) {
> + wake_up_process(curr->task);
> + list_del_init(&curr->task_list);
> + break;Just be curious, what's this break for? Or what's this loop(?) for? > + } > +} > +EXPORT_SYMBOL(swake_up_locked); > + Regards, Boqun
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