Hi Russel, On Thu, 2015-10-29 at 13:31 +0000, Russell King - ARM Linux wrote: > On Thu, Oct 29, 2015 at 01:47:35AM +0300, Alexey Brodkin wrote: > > diff --git a/lib/div64.c b/lib/div64.c > > index 62a698a..3055328 100644 > > --- a/lib/div64.c > > +++ b/lib/div64.c > > +/* > > + * If the divisor happens to be constant, we determine the appropriate > > + * inverse at compile time to turn the division into a few inline > > + * multiplications instead which is much faster. > > + */ > > uint32_t __attribute__((weak)) __div64_32(uint64_t *n, uint32_t base) > > { > > - uint64_t rem = *n; > > - uint64_t b = base; > > - uint64_t res, d = 1; > > - uint32_t high = rem >> 32; > > - > > - /* Reduce the thing a bit first */ > > - res = 0; > > - if (high >= base) { > > - high /= base; > > - res = (uint64_t) high << 32; > > - rem -= (uint64_t) (high*base) << 32; > > - } > > + unsigned int __r, __b = base; > > > > - while ((int64_t)b > 0 && b < rem) { > > - b = b+b; > > - d = d+d; > > - } > > + if (!__builtin_constant_p(__b) || __b == 0) { > > Can you explain who __builtin_constant_p(__b) can be anything but false > here? I can't see that this will ever be true. > > This is a function in its own .c file - the compiler will have no > knowledge about the callers of this function scattered throughout the > kernel, and it has to assume that the 'base' argument to this function > is variable. So, __builtin_constant_p(__b) will always be false, which > means this if () statement will always be true and the else clause will > never be used.
Essentially constant propagation will only happen if __div64_32() is inlined. For that we need to add "inline" specifier to __div64_32(), but that in its turn will prevent use of arch-specific more optimal __div64_32() implementation. And that was my main question how to implement this properly: have better generic do_div() or __div64_32() as its heavy lifting part and still keep an ability for some architectures to use their own implementations. -Alexey N�����r��y����b�X��ǧv�^�){.n�+����{����zX����ܨ}���Ơz�&j:+v�������zZ+��+zf���h���~����i���z��w���?�����&�)ߢf��^jǫy�m��@A�a��� 0��h���i