On Thu, 2015-10-29 at 17:30 +0100, Vitaly Kuznetsov wrote:
> string_get_size() can't really handle huge block sizes, especially
> blk_size > U32_MAX but string_get_size() interface states the opposite.
> Change blk_size from u64 to u32 to reflect the reality.

What is the actual evidence for this?  The calculation is designed to be
a symmetric 128 bit multiply.  When I wrote and tested it, it worked
fine for huge block sizes.

James

> Signed-off-by: Vitaly Kuznetsov <vkuzn...@redhat.com>
> ---
>  include/linux/string_helpers.h | 2 +-
>  lib/string_helpers.c           | 4 ++--
>  2 files changed, 3 insertions(+), 3 deletions(-)
> 
> diff --git a/include/linux/string_helpers.h b/include/linux/string_helpers.h
> index dabe643..1223e80 100644
> --- a/include/linux/string_helpers.h
> +++ b/include/linux/string_helpers.h
> @@ -10,7 +10,7 @@ enum string_size_units {
>       STRING_UNITS_2,         /* use binary powers of 2^10 */
>  };
>  
> -void string_get_size(u64 size, u64 blk_size, enum string_size_units units,
> +void string_get_size(u64 size, u32 blk_size, enum string_size_units units,
>                    char *buf, int len);
>  
>  #define UNESCAPE_SPACE               0x01
> diff --git a/lib/string_helpers.c b/lib/string_helpers.c
> index 5939f63..f6c27dc 100644
> --- a/lib/string_helpers.c
> +++ b/lib/string_helpers.c
> @@ -26,7 +26,7 @@
>   * at least 9 bytes and will always be zero terminated.
>   *
>   */
> -void string_get_size(u64 size, u64 blk_size, const enum string_size_units 
> units,
> +void string_get_size(u64 size, u32 blk_size, const enum string_size_units 
> units,
>                    char *buf, int len)
>  {
>       static const char *const units_10[] = {
> @@ -58,7 +58,7 @@ void string_get_size(u64 size, u64 blk_size, const enum 
> string_size_units units,
>               i++;
>       }
>  
> -     exp = divisor[units] / (u32)blk_size;
> +     exp = divisor[units] / blk_size;
>       /*
>        * size must be strictly greater than exp here to ensure that remainder
>        * is greater than divisor[units] coming out of the if below.


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