James Bottomley <jbottom...@odin.com> writes:

> On Mon, 2015-11-02 at 16:58 +0100, Vitaly Kuznetsov wrote:
>> James Bottomley <jbottom...@odin.com> writes:
>> 
>> > On Fri, 2015-10-30 at 11:46 +0100, Vitaly Kuznetsov wrote:
>> >> James Bottomley <jbottom...@odin.com> writes:
>> >> 
>> >> > On Thu, 2015-10-29 at 17:30 +0100, Vitaly Kuznetsov wrote:
>> >> >> string_get_size() can't really handle huge block sizes, especially
>> >> >> blk_size > U32_MAX but string_get_size() interface states the opposite.
>> >> >> Change blk_size from u64 to u32 to reflect the reality.
>> >> >
>> >> > What is the actual evidence for this?  The calculation is designed to be
>> >> > a symmetric 128 bit multiply.  When I wrote and tested it, it worked
>> >> > fine for huge block sizes.
>> >> 
>> >> We have 'u32 remainder' and then we do:
>> >> 
>> >> exp = divisor[units] / (u32)blk_size;
>> >> ...
>> >> remainder = do_div(size, divisor[units]);
>> >> remainder *= blk_size;
>> >> 
>> >> I'm pretty sure it will overflow for some inputs.
>> >
>> > It shouldn't; the full code snippet does this:
>> >
>> >            while (blk_size >= divisor[units]) {
>> >                    remainder = do_div(blk_size, divisor[units]);
>> >                    i++;
>> >            }
>> >
>> >            exp = divisor[units] / (u32)blk_size;
>> >
>> > So by the time it reaches the statement you complain about, blk_size is
>> > already less than or equal to the divisor (which is 1000 or 1024) so
>> > truncating to 32 bits is always correct.
>> >
>> 
>> I overlooked, sorry!
>> 
>> > I'm sort of getting the impression you don't quite understand the
>> > mathematics:  i is the logarithm to the base divisor[units].  We reduce
>> > both operands to exponents of the logarithm base (adding the two bases
>> > together in i), which means they are by definition in a range between
>> > zero and the base and then multiply the remaining exponents correcting
>> > the result for a base overflow (so the result is always a correct
>> > exponent and i is the logarithm to the base).  It's actually simply
>> > Napier's algorithm.
>> >
>> > The reason we're getting the up to 2.5% rounding errors you complain
>> > about is because at each logarithm until the last one, we throw away the
>> > remainder (it's legitimate because it's always 1000x smaller than the
>> > exponent), but in the case of a large remainder it provides a small
>> > correction to the final operation which we don't account for.  If you
>> > want to make a true correction, you save the penultimate residue in each
>> > case, multiply each by the *other* exponent add them together, divide by
>> > the base and increment the final result by the remainder.
>> 
>> My assumption was that we don't really need to support blk_sizes >
>> U32_MAX and we can simplify string_get_size() instead of adding
>> additional complexity. Apparently, the assumption was wrong.
>> 
>> >
>> > However, for 2.5% the physicist in me says the above is way overkill.
>> >
>> 
>> It is getting was over 2.5% if blk_size is not a power of 2. While it is
>> probably never the case for block subsystem the function is in lib and
>> pretends to be general-enough. I'll try to make proper correction and
>> let's see if it's worth the effort. 
>
> OK, this is the full calculation.  It also includes an arithmetic
> rounding to the final figure print.  I suppose it's not that much more
> complexity than the original, and it does make the algorithm easier to
> understand.
>
> We could do with running the comments by some other non-mathematician,
> now I've explained it in detail to you two, to see if they actually give
> an understanding of the algorithm.

Thanks, to me they look great! One nitpick below ...

>
> James
>
> ---
>
> diff --git a/lib/string_helpers.c b/lib/string_helpers.c
> index 5939f63..1ec7e77a 100644
> --- a/lib/string_helpers.c
> +++ b/lib/string_helpers.c
> @@ -44,7 +44,7 @@ void string_get_size(u64 size, u64 blk_size, const enum 
> string_size_units units,
>               [STRING_UNITS_2] = 1024,
>       };
>       int i, j;
> -     u32 remainder = 0, sf_cap, exp;
> +     u32 remainder = 0, sf_cap, r1 = 0, r2 = 0, round;
>       char tmp[8];
>       const char *unit;
>
> @@ -53,27 +53,46 @@ void string_get_size(u64 size, u64 blk_size, const enum 
> string_size_units units,
>       if (!size)
>               goto out;
>
> +     /* This is napier's algorithm.  Reduce the original block size to
> +      *
> +      * co * divisor[units]^i
> +      *
> +      * where co = blk_size + r1/divisor[units];
> +      *
> +      * and the same for size.  We simply add to the exponent i, because
> +      * the final calculation we're looking for is
> +      *
> +      * (co1 * co2) * divisor[units]^i
> +      */
> +
> +
>       while (blk_size >= divisor[units]) {
> -             remainder = do_div(blk_size, divisor[units]);
> +             r1 = do_div(blk_size, divisor[units]);
>               i++;
>       }
>
> -     exp = divisor[units] / (u32)blk_size;
> -     /*
> -      * size must be strictly greater than exp here to ensure that remainder
> -      * is greater than divisor[units] coming out of the if below.
> -      */
> -     if (size > exp) {
> -             remainder = do_div(size, divisor[units]);
> -             remainder *= blk_size;
> +     while (size >= divisor[units]) {
> +             r2 = do_div(size, divisor[units]);
>               i++;
> -     } else {
> -             remainder *= size;
>       }
>
> -     size *= blk_size;
> -     size += remainder / divisor[units];
> -     remainder %= divisor[units];
> +     /* here's the magic.  co1 * co2 may be > divisor[i], so correct for
> +      * that in the exponent and make sure that the additional corrections
> +      * from the remainders is added in.
> +      *
> +      * co1 *co2 = (blk_size + r1/divisor[units])*(size + r2/divisor[units])
> +      *
> +      * therefore
> +      *
> +      * co1*co2*divisor[units] = blk_size*size*divisor[units] +
> +      *          r1*size + r2*size + r1*r2/divisor[units]
> +      *
> +      * drop the last term because it's too small and perform the
> +      * calculation cleverly by decremeting i to be automatically dealing
> +      * with everything multiplied by divisor[units] */
> +
> +     --i;
> +     size = size * blk_size * divisor[units] + r1 * size + r2 *
> blk_size;

The last term is actually not that small. Here is an example:

size = 8192  blk_size = 1024

'As is' the algorithm gives us '8.38 MB', and if we add "+ r1 * r1 /
divisor[units]" we get '8.39 MB' (the correct answer is 8192 * 1024 =
8388608 which is 8.39).

Both r1 and r2 are < divisor[units] here so r1 * r2 won't overflow u32,
I suggest we add this term.

>
>       while (size >= divisor[units]) {
>               remainder = do_div(size, divisor[units]);
> @@ -81,8 +100,15 @@ void string_get_size(u64 size, u64 blk_size, const enum 
> string_size_units units,
>       }
>
>       sf_cap = size;
> -     for (j = 0; sf_cap*10 < 1000; j++)
> +     round = 500;
> +     for (j = 0; sf_cap*10 < 1000; j++) {
>               sf_cap *= 10;
> +             round /= 10;
> +     }
> +
> +     /* add a 5 to the digit below what will be printed to ensure
> +      * an arithmetical round up */
> +     remainder += round;
>
>       if (j) {
>               remainder *= 1000;

Can I post this solution with your Suggested-by or do you plan to do it
yourself?

Thanks,

-- 
  Vitaly
--
To unsubscribe from this list: send the line "unsubscribe linux-kernel" in
the body of a message to majord...@vger.kernel.org
More majordomo info at  http://vger.kernel.org/majordomo-info.html
Please read the FAQ at  http://www.tux.org/lkml/

Reply via email to