Hi Richard, On Wed, 13 Apr 2016 20:05:33 +0100 "Richard W.M. Jones" <[email protected]> wrote: > > It's not possible to read the process umask without also modifying it, > which is what umask(2) does. A library cannot read umask safely, > especially if the main program might be multithreaded.
I was wondering if you really need to read the umask, or would just a
"ignore umask" flag to open{,at} do what you want?
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Cheers,
Stephen Rothwell
