On Fri, 15 Jul 2016 18:13:10 +0200 Jiri Olsa <jo...@redhat.com> wrote:
> On Fri, Jul 15, 2016 at 12:02:31PM -0400, Steven Rostedt wrote: > > SNIP > > > > for "AA\1\0" this returns "1" although that should return "0". > > > > > > orig len 4 > > > decremented len 3 > > > for: > > > 0 1 > > > > > > index 2 would not be inspected. Or am I missing something? > > > > > > I think that the for check should be "i < len" > > > > Yes it should be. I think we got the two solutions mixed up. > > > > With the above len--, it should be i < len, but when we did the check > > for zero at the end, we needed the i < len - 1 > > ugh right.. should be 'i < len' check in the for loop, > > there's also the patch 2/3 that needs to be changed > I'm wondering if we should also add at the beginning: if (!len) return 0; Otherwise we will be accessing out of bounds with the len-1. -- Steve