On Thu, Aug 18, 2016 at 04:19:10PM +0800, zijun_hu wrote:
> From: zijun_hu <zijun...@htc.com>
> 
> for LP64 ABI, struct rb_node aligns at 8 bytes boundary due to
> sizeof(long) == 8 normally, so 0x07 should be used to extract
> node's parent rather than 0x03

Doesn't matter though, in practise. The remaining bits are always 0.


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