On Thu, 22 February 2007 05:30:03 +0100, Juan Piernas Canovas wrote: > > DualFS writes meta-blocks in variable-sized chunks that we call partial > segments. The meta-data device, however, is divided into segments, which > have the same size. A partial segment can be as large a a segment, but a > segment usually has more that one partial segment. Besides, a partial > segment can not cross a segment boundary.
Sure, that's a fairly common approach. > A partial segment is a transaction unit, and contains "all" the blocks > modified by a file system operation, including indirect blocks and i-nodes > (actually, it contains the blocks modified by several file system > operations, but let us assume that every partial segment only contains the > blocks modified by a single file system operation). > > So, the above figure is as follows in DualFS: > > Before: > Segment 1: [some data] [ D0 D1 D2 I ] [more data] > Segment 2: [ some data ] > Segment 3: [ empty ] > > If the datablock D0 is modified, what you get is: > > Segment 1: [some data] [ garbage ] [more data] > Segment 2: [ some data ] > Segment 3: [ D0 D1 D2 I ] [ empty ] You have fairly strict assumptions about the "Before:" picture. But what happens if those assumptions fail. To give you an example, imagine the following small script: $ for i in `seq 1000000`; do touch $i; done This will create a million dentries in one directory. It will also create a million inodes, but let us ignore those for a moment. It is fairly unlikely that you can fit a million dentries into [D0], so you will need more than one block. Let's call them [DA], [DB], [DC], etc. So you have to write out the first block [DA]. Before: Segment 1: [some data] [ DA D1 D2 I ] [more data] Segment 2: [ some data ] Segment 3: [ empty ] If the datablock D0 is modified, what you get is: Segment 1: [some data] [ garbage ] [more data] Segment 2: [ some data ] Segment 3: [ DA D1 D2 I ] [ empty ] That is exactly your picture. Fine. Next you write [DB]. Before: see above After: Segment 1: [some data] [ garbage ] [more data] Segment 2: [ some data ] Segment 3: [ DA][garbage] [ DB D1 D2 I ] [ empty] You write [DC]. Note that Segment 3 does not have enough space for another partial segment: Segment 1: [some data] [ garbage ] [more data] Segment 2: [ some data ] Segment 3: [ DA][garbage] [ DB][garbage] [wasted] Segment 4: [ DC D1 D2 I ] [ empty ] You write [DD] and [DE]: Segment 1: [some data] [ garbage ] [more data] Segment 2: [ some data ] Segment 3: [ DA][garbage] [ DB][garbage] [wasted] Segment 4: [ DC][garbage] [ DD][garbage] [wasted] Segment 5: [ DE D1 D2 I ] [ empty ] And some time later you even have to switch to a new indirect block, so you get before: Segment n : [ DX D1 D2 I ] [ empty ] After: Segment n : [ DX D1][garb] [ DY DI D2 I ] [ empty] What you end up with after all this is quite unlike you "Before" picture. Instead of this: > Segment 1: [some data] [ D0 D1 D2 I ] [more data] You may have something closer to this: > >Segment 1: [some data] [ D1 ] [more data] > >Segment 2: [some data] [ D0 ] [more data] > >Segment 3: [some data] [ D2 ] [more data] You should try the testcase and look at a dump of your filesystem afterwards. I usually just read the raw device in a hex editor. Jörn -- Beware of bugs in the above code; I have only proved it correct, but not tried it. -- Donald Knuth - To unsubscribe from this list: send the line "unsubscribe linux-kernel" in the body of a message to [EMAIL PROTECTED] More majordomo info at http://vger.kernel.org/majordomo-info.html Please read the FAQ at http://www.tux.org/lkml/