>
> > > > +
> > > > +/* Note: kernel crypto API realization */
> > > > +static int virtio_crypto_ablkcipher_setkey(struct crypto_ablkcipher
> > > > *tfm,
> > > > + const uint8_t *key,
> > > > + unsigned int keylen)
> > > > +{
> > > > + struct virtio_crypto_ablkcipher_ctx *ctx =
> > crypto_ablkcipher_ctx(tfm);
> > > > + int ret;
> > > > +
> > > > + spin_lock(&ctx->lock);
> > > > +
> > > > + if (!ctx->vcrypto) {
> > > > + /* New key */
> > > > + int node = virtio_crypto_get_current_node();
> > > > + struct virtio_crypto *vcrypto =
> > > > + virtcrypto_get_dev_node(node);
> > > > + if (!vcrypto) {
> > > > + vcrypto = virtcrypto_devmgr_get_first();
> >
> > Is this the standard way to do this? How does this work with
> > multiple crypto devices (e.g. with different capabilities)?
> >
> Actually there is a simple schedule algorithms in virtcrypto_get_dev_node(),
> which return the device used fewest on the node.
>
> If we don't find a device in the node, select the first on as default.
> But I forgot to check the first devices whether the device has started here.
>
Oh, the virtcrypto_get_dev_node() had done this work, the calling of
virtcrypto_devmgr_get_first() here is superfluous. Will remove it.
Regards,
-Gonglei
