David Miller wrote:
From: Stephen Hemminger <[EMAIL PROTECTED]>
Date: Wed, 7 Mar 2007 17:07:31 -0800
The basic calculation has to be done in 32 bits to avoid
doing 64 bit divide by 3. The value x is only 22bits max
so only need full 64 bits only for x^2.
Signed-off-by: Stephen Hemminger <[EMAIL PROTECTED]>
Applied, thanks Stephen.
What about Willy Tarreau's supposedly even faster variant?
Or does this incorporate that set of improvements?
That's what this is:
x = (2 * x + (uint32_t)div64_64(a, (uint64_t)x*(uint64_t)x)) / 3;
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