On Fri, Jun 02, 2017 at 11:46:47AM +0200, Martin Schwidefsky wrote:
> On Fri, 2 Jun 2017 09:02:10 +0200
> Heiko Carstens <[email protected]> wrote:
> > Maybe this is a bit over-simplified, but might work.
> This is not over-simplified at all, that does work:
Good!
> +struct arch_elf_state {
> +};
> +
> +#define INIT_ARCH_ELF_STATE { }
> +
> +#define arch_elf_pt_proc(ehdr, phdr, elf, interp, state) (0)
> +#define arch_check_elf(ehdr, interp, interp_ehdr, state) \
> +({ \
> + struct elf64_hdr *hdr = (void*) ehdr; \
> + int _rc = 0; \
> + if (hdr->e_ident[EI_CLASS] == ELFCLASS64 && \
> + (hdr->e_flags & 0x00000002) && \
> + !page_table_allocate_pgste && \
> + !current->mm->context.alloc_pgste) { \
> + current->mm->context.alloc_pgste = 1; \
However, I think this is over-simplified, unless I'm mistaken.
If you set current->mm->context.alloc_pgste here, then that means that 4k
page tables will be freed when the original mm will be released, instead of
the correct 2k ones.
I think you need an additional intermediate context flag here. Something
like current->mm->context.request_pgste or whatever, no?
