> Lets say that we want to do MW DMA mode 2. This has the minimum timing > of 70ns active, 25ns recovery, 120ns cycle time. > > When you quantise those figures using a clock period of 62.5ns (16MHz) > you end up with: 2 clocks active (2*62.5 > 70), 1 clock recovery > (1*62.5 > 25) and 2 clocks cycle (2*62.5 > 120). > > Last time I checked, active + recovery must always be equal to the cycle > time, and unless my math is failing me, 2 + 1 does not equal 2.
Do you mean active + recovery must be less than or equal to the cycle time? Because 70ns + 25ns does not equal 120ns either... - R. - To unsubscribe from this list: send the line "unsubscribe linux-kernel" in the body of a message to [EMAIL PROTECTED] More majordomo info at http://vger.kernel.org/majordomo-info.html Please read the FAQ at http://www.tux.org/lkml/
