Am Montag, 16. Oktober 2017, 22:50:43 CEST schrieb Daniel Borkmann: > > struct task_struct *task = current; > > > > + task_lock(task); > > > > strncpy(buf, task->comm, size); > > > > + task_unlock(task); > > Wouldn't this potentially lead to a deadlock? E.g. you attach yourself > to task_lock() / spin_lock() / etc, and then the BPF prog triggers the > bpf_get_current_comm() taking the lock again ...
Yes, but doesn't the same apply to the use case when I attach to strncpy() and run bpf_get_current_comm()? Thanks, //richard
