Hi Vincent, On Mon, Oct 30, 2017 at 9:00 AM, Vincent Guittot <[email protected]> wrote: > On 28 October 2017 at 11:59, Joel Fernandes <[email protected]> wrote: >> find_idlest_group_cpu goes through CPUs of a group previous selected by >> find_idlest_group. find_idlest_group returns NULL if the local group is the >> selected one and doesn't execute find_idlest_group_cpu if the group to which >> 'cpu' belongs to is chosen. So we're always guaranteed to call >> find_idlest_group_cpu with a group to which cpu is non-local. This makes one >> of > > Is this still true in case of overlapping topology ?
Yes, I believe so. As per the code, find_idlest_group will only return a group to which this_cpu doesn't belong to. So incase an overlapping group was returned by find_idlest_group (instead of NULL), then none of the groups (among the set of overlapping groups) is local to this_cpu. Incase NULL is returned, then find_idlest_group_cpu doesn't execute at all. Do you agree? thanks, - Joel [..]
